The FIRST_VALUE , LAST_VALUE are the two Analytical functions in the SQL Server. These are the Window functions used to return the first value, last value in an ordered set of values.
FIRST_VALUE () :
The FIRST_VALUE function returns the first value in an ordered set of values. Return type of this function is same type as scalar_expression.
Syntax:
FIRST_VALUE( )
OVER ( [ partition_by_clause ] order_by_clause )
Examples:
Suppose we have a sample of orders with 20 records with order details as follows :
Select
Order_Id, Order_date, Prod_Id, Units_Sold
From tbl_Sample
Returning First_Value of the Order_Date and Order_Id based on Order By Prod_Id , without any Partition.
Select
Order_Id, Order_Date, Prod_Id, Units_Sold,
FIRST_VALUE(Order_Date) Over ( Order by Prod_Id) as First_Order_Date,
FIRST_VALUE(Order_Id) Over ( Order by Prod_Id) as First_Order_Id
From tbl_Sample
The first value of Order_Id , Order_Date will be return for each row. Please note that, if the first value is NULL, then the result also null.
Also note that, this will return First value (not a minimum value) from Order_Id, Order_Date columns after soring the Prod_Id column in order by clause.
Returning First_Value of the Order_Date and Order_Id based on the Partition by Prod_Id and Order By Order_Date.
Select
Order_Id, Order_Date, Prod_Id, Units_Sold,
FIRST_VALUE(Order_Date) Over ( Partition By Prod_Id Order by Order_Date) as First_Order_Date,
FIRST_VALUE(Order_Id) Over ( Partition By Prod_Id Order by Order_Date) as First_Order_Id
From tbl_Sample S1
# Result :
The FIRST_VALUE function returned the first values from Order_Date, Order_Id Columns for each Partition Window, based on the column Prod_Id.
If we observe output, since the first value for First_Order_Date is 'NULL' in a Partition Window, Prod_Id = 1234, hence the result is written as the 'NULL. It is same case for Prod_Id=1237.
LAST_VALUE () :
The LAST_VALUE function returns the last value in an ordered set of values. Return type of this function is same type as scalar_expression.
While using this Function with Partition by clause, we need to use a another clause " ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING " to return the last value, otherwise it returns the CURRENT ROW value.
Syntax:
FIRST_VALUE( )
OVER ( [ partition_by_clause ] order_by_clause )
Examples:
Suppose we have a sample of orders with 20 records with order details as follows.
Scenario 1 :
Returning LAST_Value of the Order_Date and Order_Id based on Order By Prod_Id , without any Partition.
Select
Order_Id, Order_Date, Prod_Id, Units_Sold,
LAST_VALUE(Order_Date) Over ( Order by Prod_Id) as Last_Order_Date,
LAST_VALUE(Order_Id) Over ( Order by Prod_Id) as Last_Order_Id
From tbl_Sample
# Result :
Notes:
After sorting the Prod_Id as per Order by Clause, the last value in Order_Date for the Prod_Id 1234 is 'NULL' so that it returned 'NULL' as last value for those group of rows.
The LAST_VALUE function returned the last values from Order_Date, Order_Id columns for each Partition Window, based on the column Prod_Id, though we did not use the Partition by clause, it done automatically.
This may not be the case all the time. Suppose if we use as a Unique column like Order_Id in the Order by clause then it will return the Current Row, same as original Order_Id column.
Scenario 2 :
Returning LAST_Value of the Order_Date and Order_Id based on Partition by Prod_Id and Order By Order_Date.
Select
Order_Id, Order_Date, Prod_Id, Units_Sold,
LAST_VALUE(Order_Date) Over ( Partition By Prod_Id Order by Order_Date
ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as Last_Order_Date,
LAST_VALUE(Order_Id) Over ( Partition By Prod_Id Order by Order_Date
ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as Last_Order_Id
From tbl_Sample
Notes:
While using this Function with Partition by clause, we need to use a another clause " ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING " to return the last value, otherwise it returns the CURRENT ROW value.
# Result :
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Thanks, TAMATAM ; Business Intelligence & Analytics Professional
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